In order to utilize any matter just knowing a substance is not enough.
One has to know about its properties and its characteristics. There are
various methods to determine the properties of a
chemical substance.
One of the most common and most reliable methods is the method of titration.
Titration
can be broadly described as finding out the strength of an unknown
solution with a standard solution whose strength is known.
Titration is a method of finding out the
strength of a solution either in the terms of molarity or normality or
molality or acidity or alkalinity or precipitatability.Titration
can also be used to find out the presence of elements either in their
elemental state or in their compound state. Some substances get adsorbed
on the surface of other substances and this can also be estimated by
the process of titration.
Formation of complexes is the
characteristic of certain metals. Different varieties co complexes are
formed by the group of same elements and these will have different
properties. This is possible because of the change in the oxidation number of the metal which we call as variable valency.
By the method of titration the changes in the oxidation states can be established and in turn the strength of the solution. Estimation of amino acids are also done by the method of titration.
Titrations are done in liquid medium generally
between clear solutions. The solutions are measured in volumes and the
amount of the substance dissolved in the solvent gives the concentration
of the solution. The concentration of solution is in terms of molarity
or normality.
Molarity (M) is defined as the number of moles present in one litre of solution. Mole is a number which is also called Avogadro number of molecules.
Number of moles of a substance is the ratio of the mass of the substance and the molecular mass.
M = massmol mass
Normality(N) is defined as the ratio between the mass of the substance and its equivalent mass.
N = massEq mass
Equivalent mass is defined as the ratio between the molecular mass ans the valency of the substance
Eq.mass(E) = Mol massValency
In titrations the concentration of one of the solutions is known which is called standard solution or titrant. The solution of which the concentration is to be found is called aliquot or titrate.
According
to the Stoichiometric equation, a reaction takes place in equivalent
proportions. Thus the product of Volume(V) and molarity(M) or the
normality(N) of one of the solutions is equal to that of the other
solution at the equivalence point or end point of the titration.
Indicator is used to get a sharp end point in a titration.
Thus the Titration equation is
V1M1 = V2M2 Where V
1is the volume and M
1 is the molarity of standard solution. V
2 is the volume of the unknown concentration solution of which the molarity is to be found.
Therefore
M2 = V1M1V2
Concentration of the unknown solution is M X mol.mass. This is the titration equation.
Since titrations are mostly meant to find the
concentrations we can use a direct equation for titration formula. If C
k is the concentration of known solution the volume of which is found to be V
k. To find the concentration C
uk of V
uk volume of given unknown solution, the concentration.
Cuk = CkXVkVuk
This is titration formula.
End point of titration is also known as equivalence point. At this point both the titrant and titrate are in stoichiometric proportions. If it is an acid base titration
the endpoint of titration is thee point at which the acid and base are
stoichiometrically balanced in reaction and the pH of the mixture is
neutral.
The endpoint of titration is indicated sharply by a
suitable indicator either added directly to the solution or used
externally.
The titration procedure is very simple.
- The
apparatus used are a conical flask of 25mL or 50 mL or 100 mL capacity
depending on the type of titration, a pipette of suitable capacity
marking, a volumetric flask suitable to make the standard solution,
sensitive balance and a burner if heating is required.
- A
solution of known concentration is made in a volumetric flask. This
gives us the known volume and known normality or molarity.
- This is filled in a burette and the readings are noted.
- Care should be taken to avoid the presence of air gaps in the burette.
- With
the help of a pipette a fixed volume of the unknown concentration
solution is taken in a conical flask and this is called aliquot.
- A few drops of suitable indicator is added to this solution in the flask.
-
Keeping the flask under the nozzle of the burette which is fixed
vertically on a stand slowly the standard solution is run in to the
flask with consistent stirring.
- At the end point the
indicator changes its color. The same procedure is repeated several
times until concurrent values are obtained.
The common classroom examples of titrations are the
determination of the strength of NaOH solution by titrating with
Hydrochloric acid. It is not possible to make a standard solution of
NaOH by molecular mass method since it is highly hygroscopic crystals.
Similarly
hydrochloric acid is a liquid and difficult to get the exact strength.
While to conduct the experiment first a standard sodium carbonate
solution is made by weighing pure anhydrous sodium carbonate and
dissolving it in known quantity of water. This standard solution is used
to establish the strength of HCl, which in turn is used to determine
the strength of NaOH.
For a typical acid base titration in which the
strength of the base is to be found out, the calculations can be as
follows.
Base: Volume of the base taken (Pipette reading) Vb mL
Normality of the base (To be foundout) Nb mL
Acid: Volume of the acid (Burette reading) Va mL
Normality of the acid (Known) Na mL
Normality of Base
Nb = VaXNaVb
Concentration of the base in given solution in percentage is
Nb X E.W. X 100/1000 = x%
- Back titration is a slightly complicated
titration procedure than the simple or direct titration. In this one
reagent with known concentration is added in excess.
- The
volatile component of the original compound whose concentration is to be
established is allowed to react with the excess solution.
- The remaining quantity of the known reagent is titrated which will give the value that is consumed by the volatile component.
- For
example, to know the strength of Ammonium sulphate, the compound is
mixed with excess sodium hydroxide in a specially designed glass flask
(Kjehldahl flask).
- Sodium hydroxide reacts with the salt and
releases ammonia gas. The released gas is absorbed in known excess
volume of sulfuric acid.
- All the gas is driven out by heating
the flask. The excess sulfuric acid is back titrated which will give the
acid consumed by the ammonia gas which in turn gives the content of
ammonia in the salt.
Redox titration is also known as
Oxidation reduction titration.
In this type of titration the change in oxidation states give the
amount of metal present in the given unknown quality substance.
Generally these titration use oxidizing agents like Potassium permanganate and Potassium di chromate in acid medium.
- Titration is a technique of finding the concentration of a particular variety in a solution whose concentration is unknown.
- The process of titration involves two components titrant and titrate.
- Titrant
is generally the liquid of unknown concentration and titrant is the
solution the concentration of which is known and by adding which in
small quantities the process of titration is performed. The point at which the change one is looking for arrives is called end point.
- There
are varieties of titrations such as acid base titration, oxidation
reduction (redox) titrations, precipitation titrations, adsorption
titrations and complex titrations etc.,
- A titration graph or titration curve is obtained in a graph one the graph is plotted with the readings of a titration.
- Since
it is a titration of volumes and one of the volumes is generally fixed,
the other quality of the fixed volume is taken one axis.
- The
other axis is for the volume that is added to achieve the end point. A
line joining the volumes to the changing quality on the other axis is
called the titration curve.
- The advantage of the titration curve is that it gives an accurate measure and value of the titration.
- There are different varieties of titration graphs. Acid-base graph, pH graph, pKa titration graph etc.
Solved Examples
Question 1: 25 mL of sulfuric
acid is found to be a deci-normal solution. When it is titrated against
NaOH of unknown strength, it took 28.8 mL to reach the neutralization
point. Calculate the normality of NaOH and How many grams of NaOH is
required to dissolve in 2 L to get this strength solution?
Solution:
- Volume of acid = Va = 25 mL
- Normality of acid = Na = 1/10 = 0.1N
- Volume of alkali = Vb = 28.8 mL
- Normality of base = Nb = 25 X 0.1 / 28.8 = 0.0868 N
- Grams of NaOH per 1L = Normality X Mol.
- mass/ valency = 25X0.1X40/ 28.8X1 = 3.47222 g
- Grams of NaOH in 2 L = 3.472 X 2 = 6.974 g. Ans.
Question 2: What will be
medium of the resultant solution when 200 mL of deci-normal solution of
sulfuric acid is mixed with 2.12 g of anhydrous sodium carbonate. Will
it be neutral, acidic or basic?
Solution:
Molarity M = N/2 . 0.1 N = 0.05 M. That is 0.05 moles in 1L. In 200 mL it will be 0.05 X200/1000 = 0.01 moles.
106 g of Na2CO3 is 1 mole. Then 2.12 g will be 2.12/106 = 0.02 moles.
The solution is basic in nature since the molar ratio is is 1:2; 2 being the base.